NAHIDUL HASAN

OOP Java 1. What is OOP? Answer: Object-Oriented Programming (OOP) is a programming paradigm that organizes data and behavior into objects, allowing you to model real-world entities as software objects. 2. What are the four main principles of OOP? Answer: The four main principles are encapsulation, inheritance, polymorphism, and abstraction. 3. What is encapsulation? Answer: Encapsulation is the concept of bundling data (attributes) and methods (functions) that operate on that data into a single unit, i.e., a class. 4. How do you declare a class in C++? Answer: Here's an example: cpp Copy code class MyClass { public: // Data members (attributes) int data; // Member functions void display() { cout

In the IP address "10.0.0.0/16," the "/16" is a notation used to specify the subnet mask or prefix length of the IP address. It's also referred to as CIDR (Classless Inter-Domain Routing) notation. In CIDR notation, the number after the forward slash ("/") represents the number of bits that are used for the network portion of the IP address. In this case, "/16" indicates that the first 16 bits of the IP address are used for the network, and the remaining 32 - 16 = 16 bits are available for host addresses within that network. To break it down further: The IP address "10.0.0.0" is the network address. The "/16" means that the subnet mask is "255.255.0.0" in dotted-decimal notation. In binary, this is "11111111.11111111.00000000.00000000," which signifies that the first 16 bits are network bits, and the last 16 bits can be used for host addresses. So, with a "/16" subnet mask, you can have up ...

Chapter:3 Chapter:6 Bandwidth Calculation: You have a signal with a frequency of 4 kHz. Calculate the minimum bandwidth required to transmit this signal. Solution: Bandwidth (B) = 2 * Frequency (f) B = 2 * 4 kHz = 8 kHz Data Rate and Symbol Rate: If you have a signal with a symbol rate of 2400 baud and each symbol represents 8 bits, what is the data rate? Solution: Data Rate = Symbol Rate * Bits per Symbol Data Rate = 2400 baud * 8 = 19,200 bps Propagation Delay : Calculate the propagation delay for a signal traveling in a copper cable with a length of 2500 kilometers and a propagation speed of 2/3 the speed of light. Solution: Propagation Delay = Cable Length / Propagation Speed Propagation Delay = 2500 km / (2/3) * speed of light ≈ 4.5 ms Channel Capacity (Shannon's Theorem): Using Shannon's theorem, calculate the maximum achievable data rate (in bps) for a channel with a signal-to-noise ratio (SNR) of 30 dB and a bandwidth of 6 kHz. Solution: C = B * log2(1 + SN...

Database Related Viva Pattern: Code :